webrtc/tools/quality_tracking/dashboard/load_build_status.py

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#!/usr/bin/env python
#-*- coding: utf-8 -*-
# Copyright (c) 2012 The WebRTC project authors. All Rights Reserved.
#
# Use of this source code is governed by a BSD-style license
# that can be found in the LICENSE file in the root of the source
# tree. An additional intellectual property rights grant can be found
# in the file PATENTS. All contributing project authors may
# be found in the AUTHORS file in the root of the source tree.
"""Loads build status data for the dashboard."""
from google.appengine.ext import db
def _status_not_ok(status):
return status not in ('OK', 'warnings')
def _all_ok(statuses):
return filter(_status_not_ok, statuses) == []
def _get_first_entry(iterable):
if not iterable:
return None
for item in iterable:
return item
class BuildStatusLoader:
""" Loads various build status data from the database."""
def __init__(self):
pass
@staticmethod
def load_build_status_data():
"""Returns the latest conclusive build status for each bot.
The statuses OK, failed and warnings are considered to be conclusive.
The algorithm looks at the 100 most recent status entries, which should
give data on roughly the last five revisions if the number of bots stay
around 20 (The number 100 should be increased if the number of bots
increases significantly). This should give us enough data to get a
conclusive build status for all active bots.
With this limit, the algorithm will adapt automatically if a bot is
decommissioned - it will eventually disappear. The limit should not be
too high either since we will perhaps remember offline bots too long,
which could be confusing. The algorithm also adapts automatically to new
bots - these show up immediately if they get a build status for a recent
revision.
Returns:
A list of BuildStatusData entities with one entity per bot.
"""
build_status_entries = db.GqlQuery('SELECT * '
'FROM BuildStatusData '
'ORDER BY revision DESC '
'LIMIT 100')
bots_to_latest_conclusive_entry = dict()
for entry in build_status_entries:
if entry.status == 'building':
# The 'building' status it not conclusive, so discard this entry and
# pick up the entry for this bot on the next revision instead. That
# entry is guaranteed to have a status != 'building' since a bot cannot
# be building two revisions simultaneously.
continue
if bots_to_latest_conclusive_entry.has_key(entry.bot_name):
# We've already determined this bot's status.
continue
bots_to_latest_conclusive_entry[entry.bot_name] = entry
return bots_to_latest_conclusive_entry.values()
@staticmethod
def load_last_modified_at():
build_status_root = db.GqlQuery('SELECT * '
'FROM BuildStatusRoot').get()
if not build_status_root:
# Operating on completely empty database
return None
return build_status_root.last_updated_at
@staticmethod
def compute_lkgr():
""" Finds the most recent revision for which all bots are green.
Returns:
The last known good revision (as an integer) or None if there
is no green revision in the database.
Implementation note: The data store fetches stuff as we go, so we won't
read in the whole status table unless the LKGR is right at the end or
we don't have a LKGR. Bots that are offline do not affect the LKGR
computation (e.g. they are not considered to be failed).
"""
build_status_entries = db.GqlQuery('SELECT * '
'FROM BuildStatusData '
'ORDER BY revision DESC ')
first_entry = _get_first_entry(build_status_entries)
if first_entry is None:
# No entries => no LKGR
return None
current_lkgr = first_entry.revision
statuses_for_current_lkgr = [first_entry.status]
for entry in build_status_entries:
if current_lkgr == entry.revision:
statuses_for_current_lkgr.append(entry.status)
else:
# Starting on new revision, check previous revision.
if _all_ok(statuses_for_current_lkgr):
# All bots are green; LKGR found.
return current_lkgr
else:
# Not all bots are green, so start over on the next revision.
current_lkgr = entry.revision
statuses_for_current_lkgr = [entry.status]
if _all_ok(statuses_for_current_lkgr):
# There was only one revision and it was OK.
return current_lkgr
# There are no all-green revision in the database.
return None