md5: fix test program
This makes the md5-test program print something meaningful and not smash the stack. Signed-off-by: Mans Rullgard <mans@mansr.com>
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@ -162,21 +162,29 @@ void av_md5_sum(uint8_t *dst, const uint8_t *src, const int len){
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}
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#ifdef TEST
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#include <stdio.h>
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#include <inttypes.h>
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#undef printf
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#include <stdio.h>
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static void print_md5(uint8_t *md5)
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{
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int i;
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for (i = 0; i < 16; i++)
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printf("%02x", md5[i]);
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printf("\n");
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}
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int main(void){
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uint64_t md5val;
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uint8_t md5val[16];
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int i;
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uint8_t in[1000];
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for(i=0; i<1000; i++) in[i]= i*i;
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av_md5_sum( (uint8_t*)&md5val, in, 1000); printf("%"PRId64"\n", md5val);
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av_md5_sum( (uint8_t*)&md5val, in, 63); printf("%"PRId64"\n", md5val);
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av_md5_sum( (uint8_t*)&md5val, in, 64); printf("%"PRId64"\n", md5val);
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av_md5_sum( (uint8_t*)&md5val, in, 65); printf("%"PRId64"\n", md5val);
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av_md5_sum(md5val, in, 1000); print_md5(md5val);
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av_md5_sum(md5val, in, 63); print_md5(md5val);
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av_md5_sum(md5val, in, 64); print_md5(md5val);
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av_md5_sum(md5val, in, 65); print_md5(md5val);
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for(i=0; i<1000; i++) in[i]= i % 127;
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av_md5_sum( (uint8_t*)&md5val, in, 999); printf("%"PRId64"\n", md5val);
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av_md5_sum(md5val, in, 999); print_md5(md5val);
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return 0;
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}
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