cxx/test/containers/sequences/deque/deque.cons/assign_iter_iter.pass.cpp
Howard Hinnant b64f8b07c1 license change
git-svn-id: https://llvm.org/svn/llvm-project/libcxx/trunk@119395 91177308-0d34-0410-b5e6-96231b3b80d8
2010-11-16 22:09:02 +00:00

94 lines
2.2 KiB
C++

//===----------------------------------------------------------------------===//
//
// The LLVM Compiler Infrastructure
//
// This file is dual licensed under the MIT and the University of Illinois Open
// Source Licenses. See LICENSE.TXT for details.
//
//===----------------------------------------------------------------------===//
// <deque>
// template <class InputIterator>
// void assign(InputIterator f, InputIterator l);
#include <deque>
#include <cassert>
#include "../../../iterators.h"
std::deque<int>
make(int size, int start = 0 )
{
const int b = 4096 / sizeof(int);
int init = 0;
if (start > 0)
{
init = (start+1) / b + ((start+1) % b != 0);
init *= b;
--init;
}
std::deque<int> c(init, 0);
for (int i = 0; i < init-start; ++i)
c.pop_back();
for (int i = 0; i < size; ++i)
c.push_back(i);
for (int i = 0; i < start; ++i)
c.pop_front();
return c;
};
void
test(std::deque<int>& c1, const std::deque<int>& c2)
{
std::size_t c1_osize = c1.size();
c1.assign(c2.begin(), c2.end());
assert(distance(c1.begin(), c1.end()) == c1.size());
assert(c1 == c2);
}
void
testN(int start, int N, int M)
{
typedef std::deque<int> C;
typedef C::iterator I;
typedef C::const_iterator CI;
C c1 = make(N, start);
C c2 = make(M);
test(c1, c2);
}
void
testI(std::deque<int>& c1, const std::deque<int>& c2)
{
typedef std::deque<int> C;
typedef C::const_iterator CI;
typedef input_iterator<CI> ICI;
std::size_t c1_osize = c1.size();
c1.assign(ICI(c2.begin()), ICI(c2.end()));
assert(distance(c1.begin(), c1.end()) == c1.size());
assert(c1 == c2);
}
void
testNI(int start, int N, int M)
{
typedef std::deque<int> C;
typedef C::iterator I;
typedef C::const_iterator CI;
C c1 = make(N, start);
C c2 = make(M);
testI(c1, c2);
}
int main()
{
int rng[] = {0, 1, 2, 3, 1023, 1024, 1025, 2047, 2048, 2049};
const int N = sizeof(rng)/sizeof(rng[0]);
for (int i = 0; i < N; ++i)
for (int j = 0; j < N; ++j)
for (int k = 0; k < N; ++k)
testN(rng[i], rng[j], rng[k]);
testNI(1500, 2000, 1000);
}