corrected factual mistake about BSD license in the krb4.c code
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@ -56,9 +56,9 @@ krb4
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While nothing in particular says that a Kerberos4 library must use any
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While nothing in particular says that a Kerberos4 library must use any
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particular license, the one I've tried and used successfully so far
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particular license, the one I've tried and used successfully so far
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(kth-krb4) is Original BSD-licensed with the announcement clause. Some
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(kth-krb4) is partly Original BSD-licensed with the announcement
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of the code in libcurl that is written to deal with Kerberos4 likewise
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clause. Some of the code in libcurl that is written to deal with
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have such a license.
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Kerberos4 is Modified BSD-licensed.
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MIT Kerberos http://web.mit.edu/kerberos/www/dist/
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MIT Kerberos http://web.mit.edu/kerberos/www/dist/
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